The Pyramids of Egypt
The Secrets Revealed

Part V

The Orbital Periods of The Planets
as found at Giza

HI all. Some nice breakthroughs coming this week. In Part IV of this series I showed how the odd feature of 4154 inches for G3 being exactly equal to the orbital period of Mercury in relationship to the base of G1 + G3 being the height of The Great Pyramid if we use the formula "Orbital period x 10 / Pi" when orbital period = both 87.96908 days AND 4154 inches and height of G1 = 280.014278 or 13222.6 inches. To me it was simply a stunning discovery and then I went on to show that if we used as Mercury's orbital period of 87.96908 as 9068.8 inches then the orbital period of Earth would be 365.25 / 87.96908 or 4.15202705 and times 9068.8 = 37653.9 inches and when we claculate how many cubits that would be we get 37653.9 / 20.62 and we get 1826.0865 cubits and if you have looked at any of my earlier work you would immediately recognize this as being the diagoanl of G2 x PI or 1826.0864 / PI = 581.2614 and squared and divided by 2 and square rooted gives us a sqaure of .... 411.0139 within exactly 1/100 th of an inch to the mean of G2

In all the years I have been doing research at Giza for some reason I always used 440.00 cubits for G1, 411.04 cubits for G2 and 201.46 cubits for G3. I really can't remember when I first picked these measurements or from where but use them I did. I never once thought, gee maybe I should check to see precisely what the measuremnts tell us and so today that is exactly what I did. I calculated the cubits for each side of each pyramid at Giza using 20.62 inches per cubit. I do not think it has ever been done and the results are below.

For those of you who remember Clive Ross he was instrumental in getting me to study The Giza Plateau in relation to the solar system and one of his earliest postings that I remember was that G1 + G2 + G3 = orbital period of Earth and Mars. He used 440.0 + 411.04 + 201.46 to get 1052.5 and since Earth has an orbital period of 365.25 amd Mars of 686.98 days to give us 1052.23 ... close but annoyingly out 0.27. I like perfection and have always claimed that it is to be found at Giza and so it unfolds that I may have been correct all along. I did not want it to be out 0.27 cubits. It should have been exact and after about 15 years I think I have found closure, at least on this issue. Today I decided, really just for my own records so that I would not have to keep jumping to the websites, to put all of Petrie's measurements on one page so that they would be handy when I needed to consult them. What you see below is the result of that simple idea. I really wasn't looking to prove anything at the time and really just wanted a quick reference page, I was to be rewarded a million fold when, after changing every side to cubits and averaging all the sides together found much to my delight and astonishment that the mean value of all the sides when added together equalled 1053.2454. This was now corect to 1/100th of an inch but still I wanted more. There is one side that can not be checked and it is the north side of G3. If I substitue the value of 4152.3 inches then the entire complex of 3 pyramids closes to within 4/10,000 ths of an inch.(interestingly the tolerance of a billiard table ) . I was now happy ! I had finally showed that Clive was correct all along. The bases of G1 + G2 + G3 do equal the orbital period of Earth and Mars when they are added together However this opens up a whole new line of inquiry because G1 + G2 + G3 now that they eqaul 1052.23 can be seen to give us this: 1052.23 x 2 x Pi = 6611.3561 and for those of who slept through earlier pages this is preciesly 1/2 of G3 + G1 in inches or 4154 + 9068.6 = 13222.6) but wait this is 1/2 of the height of The Great Pyramid when we use G3 as Mercury's orbital period. but preciely equal to the ratio of Mercury and Ceres from this post earlier of mine where I said "Keeping with our Mercury = 4154 inches theme then Ceres would be 19.103298772 x 87.96908 = 1680.5 days or 79355.103098888 inches or 3848.45 cubits or 6612.92 feet and we find that Ceres is 1/2 the total distance of G1 + G3 in a 2 inch to 1 foot ratio or in reality a 6 to 1 ratio. That is 6 inches of Ceres equals 1 inch at Giza. Ceres is 6612.92 feet x 12 = 79,355.10 inches and since G1 + G3 = 13222.6 inches we have a 6 to 1 ratio (79,355.10 / 13222.6) or 6 to 1 (actual = 6.00147 to 1 or 99.976 %) And below please find a final image for now showing another way to find Mercury and Earth." So what does give us in mathematical formulae. Well we get that the orbital periods of Earth and Mars ( 1052.23 cubits when we multiply by 2 and times by Pi we get 6611.3561 cubits. Since this is 1/2 the distance of G1 + G3 (13222.6 / 2 = 6611.3) when added to gether IN INCHES we find that orbital period of Earth + Mars x 2 x Pi = 1/2 base of G1 + G3 IN A RATIO OF 20.62 TO 1 !!!!!!!!!!!! So in absolute values it is 1 to 2. But wait I thought G2 + G3 = Mars and G1 = Mercury so that G1 + G2 + G3 = Mars + Mercury but that equals also the orbital periods of Earth + Mars added together but wait a further minute I thought G1 + G2 + G3 equalled a cubit ?

Honestly this is starting to make my head spin with it's hidden things.


Here are some early diagram from myself and Clive Ross:

First from me:


And then one from Clive Ross





The Great Pyramid: Petrie's Measurements

Khafra's Pyramid (G2): Petrie's Measurements

Menkare's Pyramid (G3): Petrie's measurements

Orbital of Earth and Mars added together = 365.25 + 686.98 = 1052.23
So the mean average of all the sides of all 3 pyrmaids at Giza is equal to the orbital periods of Earth and Mars when added to gether (1052.23/1052.2454 = .999985)

Using the value I have filled in for the north side the mean averages of all the sides added together equals exactly the orbital periods of Earth and Mars added together.

The angles of the various Pyramids, and so-called Pyramids, are as follow:—

By photographs of the inner casings they vary from 69º to 85º; averaging 70º 12'.