The Pyramids of Egypt
The Secrets Revealed

Part IV: Section 2

An Expanded Look at
The Power of Times Ten Divided by Pi

In my earlier work on this I brought your attention to the curious fact that if you were to add the numbmer of "inches" in G1 (9068.9968) together with the number of "inches" in G3 (4154.1851) many curious things are revealed to us. The first, as I pointed out earlier, is the fact that if divide G3 "inches" by Pi we get 1322.26 and then if we multiply by ten we get 13223.1819. An extremely neat trick brought on only because G1 and G3 are in a reciprical Pi arragnement. This means that G1 + G3 = 1/ Pi and then times 10. That is to say 1 / 3.14159... x 10 or 0.31831 x 10 or 3.1831. This means that G1 + G3 = 3.1831 but we have already esatablished that G3 is divided by Pi and times 10 so 4154.18 = 1 . this makes G1 or 9068.9968 = 2.1831. Prof of this is 4154.18 x 2.1831 = 9068.9968. I will post the diagram again to make it clear.

But that is only half the story. There are three main pryamids at Giza and we have already seen that we have solved for two of them so let's solve the last one or G2. For a varietry of reasons which I ahve explained in earleir threads and posts of mine I have determiend that G1 and G2 and in the precise sq rt of 3 to Phi relationship, that is 1..73205 / 1.618034 or 1.07046627 and when we divide 9068.9968 by 1.07046627 we get: 8472.0061 and precisely what Petrie measured for the north side base of G2. So now we have the three pryamids with these measurements:

G1 = 9068.9968 (2.1831) at 440 "cubits" a "cubit" would equal 20.611356363

G2 = 8472.0061 (2.0394) at 411.0358 "cubits with "cubit" as abvoe.

G3 = 4154.1851 (1.0000) at 201.5484 " cubits" with "cubit" as abvoe.
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Total = 21,695.1880 with "cubit" at 20.611356363 = 1052.5842
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Let's leave that here for now and move on just a bit. What I have also discovered was that 13223.1819 when divided by 4Pi, or 12.566371 we get, unbelieveably 1052.2674. And as you can see extremely close to 1052.5842 from above. Since we can not change the measurements of the "inches" since they have been established from a sq rt of 3 / Pi solution, then we must adjust how many of our inches make up a "cubit". So we are left with a rather simple problem and that is: 21,695.1880 / 1052.2674 and we get ... 20.61756 as an average for our three pyramids. This leaves us:

G1 = 9068.9968 / 20.61756 = 439.8675
G2 = 8472.0061 / 20.61756 = 410.9121
G3 = 4154.1851 / 20.61756 = 201.4877
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Total = 21,695,.188 / 20.61756 = 1052.2674
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1052.2674 x 4Pi or 1052.2674 x 12.566371 = 13223.1821
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